WAEC GCE Physics OBJ/ESSAY Questions and Answers 2024 – Get Free Physics Objective/Essay Questions and Answers for the 2024 WAEC GCE November/December Exams
This announcement is for all candidates taking the 2024 WAEC General Certificate of Education (GCE) November/December examination. The Physics Objective/Essay questions and answers are now available here.
WAEC GCE Physics 2024 Exam Details:
- Subject: Physics 2 (Objective and Essay/Theory)
- Date: Thursday, 5th December 2024
- Time:
- Physics 2 (Essay): 9:30 am – 11:00 am
- Physics 1 (Objective): 11:00 am – 12:15 pm
To Get Early WAEC GCE Physics Questions and Answers, Click the Link Below 👇
WAEC GCE 2024 Physics OBJ/ESSAY Questions and Answers
We are offering free Physics Objective/Essay questions and answers for private candidates.
WAEC GCE PHYSICS THEORY (ESSAY) ANSWERS 2024:
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WAEC GCE PHYSICS OBJECTIVE (OBJ) ANSWERS 2024:
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See also:
- May/June 2024 WAEC Physics Practical Questions and Answers
- 2024 WAEC Physics (OBJ/ESSAY) Questions and Answers
- 2024 WAEC GCE Government 2nd Series (Essay & OBJ) Questions and Answers
- 2024 WAEC GCE Auto Mechanics 2nd Series OBJ/Essay Answers (14th Nov)
2024 WAEC GCE Physics Questions and Answers – Study Materials
Access the second series of WAEC GCE Nov/Dec Physics questions and answers (Objective/Essay) right here.
WAEC GCE Physics Essay Past Questions and Answers
Question 1: (a) Explain the difference between scalar and vector quantities.
(b) Give two examples of each.
(c) A car travels 100 m north and then 75 m east. Calculate its resultant displacement.
Answer 1: (a) A scalar quantity has only magnitude and no direction, while a vector quantity has both magnitude and direction.
(b) Examples:
- Scalar: Temperature, mass
- Vector: Displacement, velocity
(c) To calculate the resultant displacement, use the Pythagoras theorem:
Resultant displacement=(1002+752)=10000+5625=15625=125 m\text{Resultant displacement} = \sqrt{(100^2 + 75^2)} = \sqrt{10000 + 5625} = \sqrt{15625} = 125 \, \text{m}
The resultant displacement is 125 m at an angle to the north-east.
Question 2: (a) State Ohm’s law.
(b) A resistor of 10 Ω is connected in series with a 2 Ω resistor. If a potential difference of 24 V is applied across the combination, calculate:
(i) the total resistance in the circuit,
(ii) the current flowing through the circuit.
Answer 2: (a) Ohm’s law states that the current (I) passing through a conductor between two points is directly proportional to the voltage (V) across the two points, provided the temperature remains constant. Mathematically, V=IRV = IR, where RR is the resistance.
(b)
(i) Total resistance in series:
Rtotal=R1+R2=10 Ω+2 Ω=12 ΩR_{\text{total}} = R_1 + R_2 = 10 \, \Omega + 2 \, \Omega = 12 \, \Omega
(ii) Using Ohm’s law to find the current:
I=VR=24 V12 Ω=2 AI = \frac{V}{R} = \frac{24 \, V}{12 \, \Omega} = 2 \, A
The current flowing through the circuit is 2 A.
Question 3: (a) Define the term “latent heat of vaporization.”
(b) A 500 g block of ice at 0°C is placed in a container of boiling water at 100°C. Calculate the amount of heat required to completely melt the ice. (Latent heat of fusion of ice = 336,000 J/kg)
Answer 3: (a) The latent heat of vaporization is the amount of heat required to convert a unit mass of a liquid into vapor without a change in temperature.
(b) Calculate the heat required:
- Mass of ice, m=0.5 kgm = 0.5 \, \text{kg}
- Latent heat of fusion, Lf=336,000 J/kgL_f = 336,000 \, \text{J/kg}
Q=m×Lf=0.5 kg×336,000 J/kg=168,000 JQ = m \times L_f = 0.5 \, \text{kg} \times 336,000 \, \text{J/kg} = 168,000 \, \text{J}
The amount of heat required to completely melt the ice is 168,000 J.
WAEC GCE Physics Objective Past Questions and Answers
1. Which of the following is a scalar quantity?
A. Velocity
B. Displacement
C. Force
D. Energy
Answer: D. Energy
2. The S.I. unit of electric charge is:
A. Volt
B. Joule
C. Coulomb
D. Ohm
Answer: C. Coulomb
3. When a force of 10 N moves an object by 5 m in the direction of the force, the work done is:
A. 50 J
B. 2 J
C. 15 J
D. 5 J
Answer: A. 50 J
(Work done ( = \text{Force} \times \text{Distance} = 10 , \text{N} \times 5 , \text{m} = 50 , \text{J})
